幻彩燈珠介紹

一、幻彩燈珠其實(shí)我們可以理解為該燈珠內(nèi)部有一顆LED驅(qū)動(dòng)芯片外加R,G,B 3種顏色的LED的合封體。并且這顆LED驅(qū)動(dòng)芯片可以驅(qū)動(dòng)3路 LED，每一路LED驅(qū)動(dòng)都跟內(nèi)部的R,G,B通過(guò)封裝打線連接好了。

1、幻彩燈珠的應(yīng)用場(chǎng)所：

(1)、家庭照明?；貌薀糁榭梢詰?yīng)用于家庭中的各種照明場(chǎng)景，如客廳、臥室、廚房等。多彩變幻的顏色可以為家庭營(yíng)造出溫馨、浪漫的氛圍。

(2)、商業(yè)場(chǎng)所。幻彩燈珠可以應(yīng)用于商業(yè)場(chǎng)所的裝飾和照明，如商場(chǎng)、酒店、ktv等。多彩變幻的顏色可以為商業(yè)場(chǎng)所營(yíng)造出藝術(shù)感和時(shí)尚感。

(3)、戶外景觀。幻彩燈珠可以應(yīng)用于城市公園、廣場(chǎng)、橋梁等戶外景觀，為城市增添藝術(shù)氣息和夜間景觀

2、幻彩燈珠對(duì)比傳統(tǒng)燈珠優(yōu)缺點(diǎn)：

(1)、顏色多彩變幻。幻彩燈珠的多彩變幻可以為家庭、商業(yè)場(chǎng)所等營(yíng)造出良好的氛圍

(2)、相比傳統(tǒng)的三基色LED燈珠+外置LED驅(qū)動(dòng)芯片體積要小，更容易生產(chǎn)

(3)、相比傳統(tǒng)的LED燈珠+外置LED驅(qū)動(dòng)芯片 成本更低

幻彩燈珠內(nèi)置驅(qū)動(dòng)芯片介紹

一、市場(chǎng)常見(jiàn)的有WS2812，SM16703P，目前我們公司推出了AD2203芯片，該芯片性價(jià)比更高。

AD2203是三通道LED驅(qū)動(dòng)IC，內(nèi)部集成有MCU數(shù)字接口、數(shù)據(jù)鎖存器、LED驅(qū)動(dòng)等電路。通過(guò)外圍MCU控制實(shí)現(xiàn)該芯片的單獨(dú)灰度、級(jí)聯(lián)控制實(shí)現(xiàn)戶外大屏的彩色點(diǎn)陣發(fā)光控制 。 主要特征: 默認(rèn)上電燈不亮，恒流12mA(可定制）,256級(jí)灰度可調(diào)，數(shù)據(jù)自動(dòng)整形，傳輸數(shù)率800---1200KHz,標(biāo)準(zhǔn)應(yīng)用電壓5V

管腳定義

具體參數(shù)如下:

六、通訊方式和應(yīng)用電路

芯片設(shè)計(jì)為單線歸零碼通訊方式。芯片上電復(fù)位以后，接收DIN 的數(shù)據(jù)，足24 bit 后，DOUT 端口開(kāi)始轉(zhuǎn)發(fā)數(shù)據(jù)，輸出到下一個(gè)芯片。在轉(zhuǎn)發(fā)之前DOUT=0電位。芯片 OUTR、OUTG、OUTB 三個(gè)端口可輸出相應(yīng)24 bit 數(shù)據(jù)的不同占空比的信號(hào)。如果DIN 端輸入信號(hào)為RESET 信號(hào)，芯片將接收到的數(shù)據(jù)送顯示，芯片將在該信號(hào)結(jié)束后重新接收新的數(shù)據(jù)，在接收完開(kāi)始的 24bit 數(shù)據(jù)后，通過(guò)DOUT口轉(zhuǎn)發(fā)數(shù)據(jù)，芯片在沒(méi)有接收到RESET 碼前，OUTR、OUTG、OUTB 管腳原輸出亮度保持不變，當(dāng)接收到不小于80μs 低電平RESET 碼后，芯片將剛才接收到的24 bit 亮度數(shù)據(jù)輸出到OUTR、OUTG、OUTB 引腳上。 七、數(shù)據(jù)編碼格式

T0H: 350ns T0L: 800ns T1H: 800ns T1L: 350ns (容錯(cuò)20%） Trst > 80us

八、級(jí)連方法

九、數(shù)據(jù)傳輸方法

單芯片24BIT數(shù)據(jù)發(fā)送順序：高位先發(fā)，即R7先發(fā)送

十、典型應(yīng)用電路

AD2202 應(yīng)用編程之炫彩漸變效果(MCU 應(yīng)廣150C)

#include "extern.h"

byte red, green, blue; //Could save these three bytes by using the rgb EWORD directly ( rgb$0, rgb$1, rgb$2)
byte mode;
byte hueinc;
byte firstinc;
EWORD rgb;
word pixels; //Only has to be a word if number of pixels > 255
word firstPixelHue;

#define definedPIXELS 300;//像素點(diǎn)

bit LED : pa.6;
bit BTN : pa.4;

int count;
//====================bit1
send1 MACRO
SET1 LED;
.DELAY 5;
$ LED low;
// .DELAY 1; //Going around is enough delay
ENDM
//===================bit0
send0 MACRO
SET1 LED;
.DELAY 2;
$ LED low;
.DELAY 2;
ENDM
//========================

void SendRGB (void)
{
DISGINT; //Let's not get interrupted

.FOR bitno, <23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0> //Regular for() loop doesn't work, but at least the compiler can do the hard work
if (rgb.bitno == 0)
{
send0;
}
else
{
send1;
}
.ENDM
ENGINT;
}

void show (void) {
rgb$0 = blue; //I lost track of MSB, LSB and endians.. This is what works. ????????
rgb$1 = red;
rgb$2 = green;
SendRGB();
}

void clearLED (void)
{
rgb = 0;
//pixels = definedPIXELS;
pixels = 300; //Debug
do
{
SendRGB();
} while (--pixels);
.delay 2000; //If you want to make sure the LED-reset is caught, use a longer one. 0.125us *2000 = 250us

}

void FPPA0 (void)
{
.ADJUST_IC SYSCLK=IHRC/2 // SYSCLK=IHRC/2 16MH 2?? 8M

count = 0;

$ T16M IHRC, /4, BIT15; // BIT15 Time increment of each T16M = 16MHz / 4 = 4 MHz
// generate INTRQ.T16 = 16,384 uS every 2^16 times
ENGINT;
$ INTEN T16; // Enable the T16M interrupt

$ LED out,low; //LED ????? ???
$ BTN in, pull; //?????????
count = 0;
unsigned word hue = 0;
firstPixelHue = 0;
byte current;
mode = 0;
firstinc = 1;

//Let's start by clearing LED's and going to sleep - we don't want anything to consume current if we restarted by mistake
clearLED();
rgb = 0;
SendRGB();//
$ LED high;
CLKMD = 0xF4; // -> ILRC
CLKMD.En_IHRC = 0; // close IHRC
while (1)
{
STOPSYS;

if (BTN == 0) break; // examine and determine whether toggle to STOPSYS or execute at high speed.
}
CLKMD = 0x34; // -> IHRC / 2
count = 0; //

//========================???===========================================
while (1) //Main loop
{
if ( BTN == 1)
{ //If button is not pressed
pixels = definedPIXELS;//300

if (mode < 3)?
{ //Rainbow
hue = firstPixelHue;//0
if (mode == 0)
{
hueinc = 5;
firstinc = 1;
}
if (mode == 1) hueinc = 0;
if (mode == 2)
{
hueinc = 10;
firstinc = 0;
}

do
{
if (hue>=768)
{
hue -= 768;
}
current = (hue & 0xFF);
if (hue < 256)
{
red = ~current;
green = current;
blue = 0;
show();
}

if (hue > 255 && hue < 512)
{
red = 0;
green = ~current;
blue = current;
show();
}

if (hue > 511 && hue < 768)
{
red = current;
green = 0;
blue = ~current;
show();
}
hue+=hueinc;

} while (--pixels);

.delay(8000); //Should be increased if fewer LED's are used
firstPixelHue+=firstinc;
if (firstPixelHue > 3072) firstPixelHue = 0; //Has to be reset sometime.
} //End rainbow

//=================??======================
if (mode == 3)
{ //Red - not too bright
red = 150;
green = 0;
blue = 0;
do {

show();
} while (--pixels);
.delay(2000);
}
//=================??=======================
if (mode == 4)
{ //Green - not too bright
red = 0;
green = 150;
blue = 0;
do {
show();
} while (--pixels);
.delay(2000);
}
//====================??==================
if (mode == 5)
{ //Blue - not too bright
red = 0;
green = 0;
blue = 125;
do {
show();
} while (--pixels);
.delay(2000);
}

if (mode == 6)
{ //Princess! - not too bright
green = 0;
red = 200;
blue = 200;
do {
show();
} while (--pixels);
.delay(2000);
}
}
else
{ //Button pressed - go to sleep
clearLED();
rgb = 0;
SendRGB();
$ LED high; //I think I remember something about setting the WS2812B signal line high, reduces leak current. Maybe not.

if (count > 10)
{ //Unless we just woke up go to sleep
//Maybe disable wakeup from other pins - PADIER
CLKMD = 0xF4; // -> ILRC
CLKMD.En_IHRC = 0; // close IHRC
while (1)
{
STOPSYS;
if (BTN == 0) break; // examine and determine whether toggle to STOPSYS or execute at high speed.
}
CLKMD = 0x34; // -> IHRC / 2
mode++;
if (mode > 6) mode = 0;
}

/* //Change mode if button held longer when coming out of sleep
count = 0;
while (count < 30) {
if (BTN == 1) {

break;
}
}
*/
count = 0;
}
// wdreset;
}
}

void Interrupt (void)
{
pushaf;
if (Intrq.T16)
{
Intrq.T16 = 0;
count ++; // 16,384uS 61 == 999,424 uS ≤ 1S
}
popaf;
}

審核編輯黃宇